NCERT Solutions for Class 9 Maths Exercise 2.3 Question 3

NCERT Solutions for Class 9 Maths Exercise 2.3 Question 3

NCERT Solutions for Class 9 Maths Exercise 2.3 Question 3

ncert-solutions-for-class-9-maths-exercise-2-3-question-3

Understanding the Question 🧐

To check if one polynomial is a factor of another, we can use the Factor Theorem. This theorem is a special case of the Remainder Theorem.

Factor Theorem: A polynomial &&g(x)&& is a factor of a polynomial &&p(x)&& if and only if the remainder is zero when &&p(x)&& is divided by &&g(x)&&.

So, our goal is to find the remainder. If the remainder is 0, it’s a factor. If not, it isn’t.

Check whether &&7 + 3x&& is a factor of &&3x^3 + 7x&&.


Applying the Factor Theorem 📝

Step 1: Identify the polynomials.

The polynomial (dividend) is &&p(x) = 3x^3 + 7x&&.

The potential factor (divisor) is &&g(x) = 7 + 3x&&.

Step 2: Find the zero of the potential factor &&g(x)&&.

To do this, we set &&g(x) = 0&& and solve for &&x&&:

&&7 + 3x = 0&&

&&3x = -7&&

&&x = -\frac{7}{3}&&

Step 3: Substitute this zero into the main polynomial &&p(x)&& to find the remainder.

We need to calculate &&p(-\frac{7}{3})&&:

&&p(-\frac{7}{3}) = 3(-\frac{7}{3})^3 + 7(-\frac{7}{3})&&

Step 4: Simplify the expression.

&&= 3(-\frac{7 \times 7 \times 7}{3 \times 3 \times 3}) – \frac{49}{3}&&

&&= 3(-\frac{343}{27}) – \frac{49}{3}&&

We can cancel a 3 from the numerator and denominator:

&&= -\frac{343}{9} – \frac{49}{3}&&

To subtract, we find a common denominator (9):

&&= -\frac{343}{9} – \frac{49 \times 3}{3 \times 3}&&

&&= -\frac{343}{9} – \frac{147}{9}&&

&&= \frac{-343 – 147}{9} = \frac{-490}{9}&&

Step 5: Check if the remainder is zero.

The remainder is &&-\frac{490}{9}&&, which is not equal to 0.

Conclusion: Since the remainder is not 0, &&7 + 3x&& is not a factor of &&3x^3 + 7x&&.


💡 Trick: The Factor Theorem is the key. Remainder = 0 means “Yes, it’s a factor.” Remainder ≠ 0 means “No, it’s not.” It’s that simple!

FAQ ❓

Q: What is the Factor Theorem?

A: The Factor Theorem says that a linear polynomial &&(x – a)&& is a factor of another polynomial &&p(x)&& if and only if &&p(a) = 0&&. It’s a quick way to check for factors without doing long division.

Q: How is the Factor Theorem related to the Remainder Theorem?

A: The Factor Theorem is a special outcome of the Remainder Theorem. The Remainder Theorem finds the remainder (&&p(a)&&). The Factor Theorem just checks if that specific remainder is zero.

Further Reading 📖

To learn more about the Factor Theorem and finding factors of polynomials, you can refer to the official NCERT textbook for Class 9 Maths, Chapter 2. More resources are available on the NCERT website at https://ncert.nic.in/.

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